Find roots of polynomial $$ p(x) = 4x^2-40x+90 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 6.5811\\[1 em]x_2 &= 3.4189 \end{aligned} $$Explanation
The solutions of $ 4x^2-40x+90 = 0 $ are: $ x = 5-\dfrac{\sqrt{ 10 }}{ 2 } ~ \text{and} ~ x = 5+\dfrac{\sqrt{ 10 }}{ 2 }$.
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