Find roots of polynomial $$ p(x) = 4x^2-20x+29 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 5 }{ 2 }+i\\[1 em]x_2 &= \frac{ 5 }{ 2 }-i \end{aligned} $$Explanation
The solutions of $ 4x^2-20x+29 = 0 $ are: $ x = \dfrac{ 5 }{ 2 }+i ~ \text{and} ~ x = \dfrac{ 5 }{ 2 }-i$.
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