The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 3\\[1 em]x_2 &= \frac{ 3 }{ 4 } \end{aligned} $$The solutions of $ 4x^2-15x+9 = 0 $ are: $ x = \dfrac{ 3 }{ 4 } ~ \text{and} ~ x = 3$.
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