Find roots of polynomial $$ p(x) = 4x^2-14x+13 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 7 }{ 4 }+\frac{\sqrt{ 3 }}{ 4 }i\\[1 em]x_2 &= \frac{ 7 }{ 4 }- \frac{\sqrt{ 3 }}{ 4 }i \end{aligned} $$Explanation
The solutions of $ 4x^2-14x+13 = 0 $ are: $ x = \dfrac{ 7 }{ 4 }+\dfrac{\sqrt{ 3 }}{ 4 }i ~ \text{and} ~ x = \dfrac{ 7 }{ 4 }-\dfrac{\sqrt{ 3 }}{ 4 }i$.
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