Find roots of polynomial $$ p(x) = 4s^2-4s+1 $$
Answer
The root of polynomial $ p(s) $ is:
$$ \begin{aligned}s &= \frac{ 1 }{ 2 } \end{aligned} $$Explanation
The solution of $ ~ 4s^2-4s+1 = 0 ~$ is $~ s = \dfrac{ 1 }{ 2 } ~$.
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