Find roots of polynomial $$ p(x) = 4h^2+7h+3 $$
Answer
The roots of polynomial $ p(h) $ are:
$$ \begin{aligned}h_1 &= -\frac{ 3 }{ 4 }\\[1 em]h_2 &= -1 \end{aligned} $$Explanation
The solutions of $ 4h^2+7h+3 = 0 $ are: $ h = -1 ~ \text{and} ~ h = -\dfrac{ 3 }{ 4 }$.
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