The roots of polynomial $ p(c) $ are:
$$ \begin{aligned}c_1 &= 1\\[1 em]c_2 &= \frac{ 3 }{ 4 } \end{aligned} $$The solutions of $ 4c^2-7c+3 = 0 $ are: $ c = \dfrac{ 3 }{ 4 } ~ \text{and} ~ c = 1$.
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