Find roots of polynomial $$ p(x) = 49x^2-149x+525 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 149 }{ 98 }+\frac{\sqrt{ 80699 }}{ 98 }i\\[1 em]x_2 &= \frac{ 149 }{ 98 }- \frac{\sqrt{ 80699 }}{ 98 }i \end{aligned} $$Explanation
The solutions of $ 49x^2-149x+525 = 0 $ are: $ x = \dfrac{ 149 }{ 98 }+\dfrac{\sqrt{ 80699 }}{ 98 }i ~ \text{and} ~ x = \dfrac{ 149 }{ 98 }-\dfrac{\sqrt{ 80699 }}{ 98 }i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator