Find roots of polynomial $$ p(x) = 45x^2+40x-100 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 10 }{ 9 }\\[1 em]x_2 &= -2 \end{aligned} $$Explanation
The solutions of $ 45x^2+40x-100 = 0 $ are: $ x = -2 ~ \text{and} ~ x = \dfrac{ 10 }{ 9 }$.
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