Find roots of polynomial $$ p(x) = 400x^2+120x+9 $$
Answer
The root of polynomial $ p(x) $ is:
$$ \begin{aligned}x &= -\frac{ 3 }{ 20 } \end{aligned} $$Explanation
The solution of $ ~ 400x^2+120x+9 = 0 ~$ is $~ x = -\dfrac{ 3 }{ 20 } ~$.
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