Find roots of polynomial $$ p(x) = 3y^2-80y-75 $$
Answer
The roots of polynomial $ p(y) $ are:
$$ \begin{aligned}y_1 &= 27.5733\\[1 em]y_2 &= -0.9067 \end{aligned} $$Explanation
The solutions of $ 3y^2-80y-75 = 0 $ are: $ y = \dfrac{ 40 }{ 3 }-\dfrac{ 5 \sqrt{ 73}}{ 3 } ~ \text{and} ~ y = \dfrac{ 40 }{ 3 }+\dfrac{ 5 \sqrt{ 73}}{ 3 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator