Find roots of polynomial $$ p(x) = 3x^7-9x^6+2x^5+3x^4-x^3-2x^2-4x-5 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2.6529\\[1 em]x_2 &= -0.0932+0.8156i\\[1 em]x_3 &= -0.0932-0.8156i\\[1 em]x_4 &= -0.7317+0.3276i\\[1 em]x_5 &= -0.7317-0.3276i\\[1 em]x_6 &= 0.9984+0.6736i\\[1 em]x_7 &= 0.9984-0.6736i \end{aligned} $$Explanation
Polynomial $ 3x^7-9x^6+2x^5+3x^4-x^3-2x^2-4x-5 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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