Find roots of polynomial $$ p(x) = 3x^4-6x^3-8x^2+22x+11 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.4561\\[1 em]x_2 &= -1.6092\\[1 em]x_3 &= 2.0327+0.9294i\\[1 em]x_4 &= 2.0327-0.9294i \end{aligned} $$Explanation
Polynomial $ 3x^4-6x^3-8x^2+22x+11 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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