Find roots of polynomial $$ p(x) = 3x^2+x+1 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -\frac{ 1 }{ 6 }+\frac{\sqrt{ 11 }}{ 6 }i\\[1 em]x_2 &= -\frac{ 1 }{ 6 }- \frac{\sqrt{ 11 }}{ 6 }i \end{aligned} $$Explanation
The solutions of $ 3x^2+x+1 = 0 $ are: $ x = -\dfrac{ 1 }{ 6 }+\dfrac{\sqrt{ 11 }}{ 6 }i ~ \text{and} ~ x = -\dfrac{ 1 }{ 6 }-\dfrac{\sqrt{ 11 }}{ 6 }i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator