Find roots of polynomial $$ p(x) = 3x^2+6x+9 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -1+\sqrt{ 2 }i\\[1 em]x_2 &= -1-\sqrt{ 2 }i \end{aligned} $$Explanation
The solutions of $ 3x^2+6x+9 = 0 $ are: $ x = -1+\sqrt{ 2 }i ~ \text{and} ~ x = -1-\sqrt{ 2 }i$.
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