Find roots of polynomial $$ p(x) = 3x^2+42x-3 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.0711\\[1 em]x_2 &= -14.0711 \end{aligned} $$Explanation
The solutions of $ 3x^2+42x-3 = 0 $ are: $ x = -7-5 \sqrt{ 2 } ~ \text{and} ~ x = -7+5 \sqrt{ 2 }$.
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