Find roots of polynomial $$ p(x) = 3x^2+36 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2 \sqrt{ 3 }i\\[1 em]x_2 &= -2 \sqrt{ 3 }i \end{aligned} $$Explanation
The solutions of $ 3x^2+36 = 0 $ are: $ x = 2 \sqrt{ 3 } i ~ \text{and} ~ x = -2 \sqrt{ 3 } i $.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator