Find roots of polynomial $$ p(x) = 3x^2+25 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 5 \sqrt{ 3}}{ 3 }i\\[1 em]x_2 &= -5 \frac{\sqrt{ 3 }}{ 3 }i \end{aligned} $$Explanation
The solutions of $ 3x^2+25 = 0 $ are: $ x = \dfrac{ 5 \sqrt{ 3}}{ 3 } i ~ \text{and} ~ x = -5 \dfrac{\sqrt{ 3 }}{ 3 } i $.
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