Find roots of polynomial $$ p(x) = 3x^2+18x-329 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 7.8934\\[1 em]x_2 &= -13.8934 \end{aligned} $$Explanation
The solutions of $ 3x^2+18x-329 = 0 $ are: $ x = -3-\dfrac{ 2 \sqrt{ 267}}{ 3 } ~ \text{and} ~ x = -3+\dfrac{ 2 \sqrt{ 267}}{ 3 }$.
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