Find roots of polynomial $$ p(x) = 3x^2-6x+16 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1+\frac{\sqrt{ 39 }}{ 3 }i\\[1 em]x_2 &= 1- \frac{\sqrt{ 39 }}{ 3 }i \end{aligned} $$Explanation
The solutions of $ 3x^2-6x+16 = 0 $ are: $ x = 1+\dfrac{\sqrt{ 39 }}{ 3 }i ~ \text{and} ~ x = 1-\dfrac{\sqrt{ 39 }}{ 3 }i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator