Find roots of polynomial $$ p(x) = 3x^2-2x-9 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2.0972\\[1 em]x_2 &= -1.4305 \end{aligned} $$Explanation
The solutions of $ 3x^2-2x-9 = 0 $ are: $ x = \dfrac{ 1 }{ 3 }-\dfrac{ 2 \sqrt{ 7}}{ 3 } ~ \text{and} ~ x = \dfrac{ 1 }{ 3 }+\dfrac{ 2 \sqrt{ 7}}{ 3 }$.
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