Find roots of polynomial $$ p(x) = 3x^2-27+56 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{\sqrt{ 87 }}{ 3 }i\\[1 em]x_2 &= - \frac{\sqrt{ 87 }}{ 3 }i \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ 3x^2 \color{blue}{-27} + \color{blue}{56} = 3x^2+ \color{blue}{29} $$Step 2:
The solutions of $ 3x^2+29 = 0 $ are: $ x = \dfrac{\sqrt{ 87 }}{ 3 } i ~ \text{and} ~ x = - \dfrac{\sqrt{ 87 }}{ 3 } i $.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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