Find roots of polynomial $$ p(x) = 3x^2-24x-48 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 9.6569\\[1 em]x_2 &= -1.6569 \end{aligned} $$Explanation
The solutions of $ 3x^2-24x-48 = 0 $ are: $ x = 4-4 \sqrt{ 2 } ~ \text{and} ~ x = 4+4 \sqrt{ 2 }$.
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