Find roots of polynomial $$ p(x) = 3x^2-10x+59 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 5 }{ 3 }+\frac{ 2 \sqrt{ 38}}{ 3 }i\\[1 em]x_2 &= \frac{ 5 }{ 3 }-2 \frac{\sqrt{ 38 }}{ 3 }i \end{aligned} $$Explanation
The solutions of $ 3x^2-10x+59 = 0 $ are: $ x = \dfrac{ 5 }{ 3 }+\dfrac{ 2 \sqrt{ 38}}{ 3 }i ~ \text{and} ~ x = \dfrac{ 5 }{ 3 }-\dfrac{ 2 \sqrt{ 38}}{ 3 }i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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