Find roots of polynomial $$ p(x) = 3s^2+12s+9 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -1\\[1 em]s_2 &= -3 \end{aligned} $$Explanation
The solutions of $ 3s^2+12s+9 = 0 $ are: $ s = -3 ~ \text{and} ~ s = -1$.
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