Find roots of polynomial $$ p(x) = 3s^2+12s+8 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -0.8453\\[1 em]s_2 &= -3.1547 \end{aligned} $$Explanation
The solutions of $ 3s^2+12s+8 = 0 $ are: $ s = -2-\dfrac{ 2 \sqrt{ 3}}{ 3 } ~ \text{and} ~ s = -2+\dfrac{ 2 \sqrt{ 3}}{ 3 }$.
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