Find roots of polynomial $$ p(x) = 3m^2-20m-63 $$
Answer
The roots of polynomial $ p(m) $ are:
$$ \begin{aligned}m_1 &= 9\\[1 em]m_2 &= -\frac{ 7 }{ 3 } \end{aligned} $$Explanation
The solutions of $ 3m^2-20m-63 = 0 $ are: $ m = -\dfrac{ 7 }{ 3 } ~ \text{and} ~ m = 9$.
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