Find roots of polynomial $$ p(x) = 3c^2-12c+8 $$
Answer
The roots of polynomial $ p(c) $ are:
$$ \begin{aligned}c_1 &= 3.1547\\[1 em]c_2 &= 0.8453 \end{aligned} $$Explanation
The solutions of $ 3c^2-12c+8 = 0 $ are: $ c = 2-\dfrac{ 2 \sqrt{ 3}}{ 3 } ~ \text{and} ~ c = 2+\dfrac{ 2 \sqrt{ 3}}{ 3 }$.
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