Find roots of polynomial $$ p(x) = 36x^3-90x^2+50x $$

The roots of polynomial $ p(x) $ are:

$$ \begin{aligned}x_1 &= 0\\[1 em]x_2 &= \frac{ 5 }{ 3 }\\[1 em]x_3 &= \frac{ 5 }{ 6 } \end{aligned} $$

Step 1:

Factor out $ \color{blue}{ 2x }$ from $ 36x^3-90x^2+50x $ and solve two separate equations:

$$ \begin{aligned} 36x^3-90x^2+50x & = 0\\[1 em] \color{blue}{ 2x }\cdot ( 18x^2-45x+25 ) & = 0 \\[1 em] \color{blue}{ 2x = 0} ~~ \text{or} ~~ 18x^2-45x+25 & = 0 \end{aligned} $$

One solution is $ \color{blue}{ x = 0 } $. Use second equation to find the remaining roots.

Step 2:

The solutions of $ 18x^2-45x+25 = 0 $ are: $ x = \dfrac{ 5 }{ 6 } ~ \text{and} ~ x = \dfrac{ 5 }{ 3 }$.

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.

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