Find roots of polynomial $$ p(x) = 3-2x-x^2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1\\[1 em]x_2 &= -3 \end{aligned} $$Explanation
Step 1:
Write polynomial in descending order
$$ \begin{aligned} 3-2x-x^2 & = 0\\[1 em] -x^2-2x+3 & = 0 \end{aligned} $$Step 2:
The solutions of $ -x^2-2x+3 = 0 $ are: $ x = -3 ~ \text{and} ~ x = 1$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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