Find roots of polynomial $$ p(x) = 2z^2-5z-2 $$
Answer
The roots of polynomial $ p(z) $ are:
$$ \begin{aligned}z_1 &= 2.8508\\[1 em]z_2 &= -0.3508 \end{aligned} $$Explanation
The solutions of $ 2z^2-5z-2 = 0 $ are: $ z = \dfrac{ 5 }{ 4 }-\dfrac{\sqrt{ 41 }}{ 4 } ~ \text{and} ~ z = \dfrac{ 5 }{ 4 }+\dfrac{\sqrt{ 41 }}{ 4 }$.
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