Find roots of polynomial $$ p(x) = 2x^8+7x^7+x^6-9x^5+3x^4+2x^3+3x^2-5x-7 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.7439\\[1 em]x_2 &= 1.055\\[1 em]x_3 &= -2.1575\\[1 em]x_4 &= -2.4502\\[1 em]x_5 &= 0.7372+0.7139i\\[1 em]x_6 &= 0.7372-0.7139i\\[1 em]x_7 &= -0.339+0.8283i\\[1 em]x_8 &= -0.339-0.8283i \end{aligned} $$Explanation
Polynomial $ 2x^8+7x^7+x^6-9x^5+3x^4+2x^3+3x^2-5x-7 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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