Find roots of polynomial $$ p(x) = 2x^7+3x^5-9x^2+6 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.748\\[1 em]x_2 &= 0.9211+0.1928i\\[1 em]x_3 &= 0.9211-0.1928i\\[1 em]x_4 &= -0.8747+0.9947i\\[1 em]x_5 &= -0.8747-0.9947i\\[1 em]x_6 &= 0.3276+1.5729i\\[1 em]x_7 &= 0.3276-1.5729i \end{aligned} $$Explanation
Polynomial $ 2x^7+3x^5-9x^2+6 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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