Find roots of polynomial $$ p(x) = 2x^6-x^5-x^4-x^3-4x^2-12x-36 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -1.4842\\[1 em]x_2 &= 2.0168\\[1 em]x_3 &= 0.7704+1.4657i\\[1 em]x_4 &= 0.7704-1.4657i\\[1 em]x_5 &= -0.7867+1.2547i\\[1 em]x_6 &= -0.7867-1.2547i \end{aligned} $$Explanation
Polynomial $ 2x^6-x^5-x^4-x^3-4x^2-12x-36 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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