Find roots of polynomial $$ p(x) = 2x^6-3x^5+4x^4-x^2+1 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.6448+0.4836i\\[1 em]x_2 &= 0.6448-0.4836i\\[1 em]x_3 &= -0.5141+0.3586i\\[1 em]x_4 &= -0.5141-0.3586i\\[1 em]x_5 &= 0.6193+1.2554i\\[1 em]x_6 &= 0.6193-1.2554i \end{aligned} $$Explanation
Polynomial $ 2x^6-3x^5+4x^4-x^2+1 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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