Find roots of polynomial $$ p(x) = 2x^5+x^3-4x^2-2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.2599\\[1 em]x_2 &= 0.7071i\\[1 em]x_3 &= -0.7071i\\[1 em]x_4 &= -0.63+1.0911i\\[1 em]x_5 &= -0.63-1.0911i \end{aligned} $$Explanation
Polynomial $ 2x^5+x^3-4x^2-2 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
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