Find roots of polynomial $p (x) = 2 x^{5} + 4 x^{3}$

Answer

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} x_{3} = 0 = 2 i = - 2 i$

Explanation

Step 1:

Factor out $2 x^{3}$ from $2 x^{5} + 4 x^{3}$ and solve two separate equations:

2 x^{5} + 4 x^{3} 2 x^{3} \cdot (x^{2} + 2) 2 x^{3} = 0 or x^{2} + 2 = 0 = 0 = 0

One solution is $x = 0$ . Use second equation to find the remaining roots.

Step 2:

The solutions of $x^{2} + 2 = 0$ are: $x = 2 i and x = - 2 i$ .

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.

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Find roots of polynomial p(x)=2x5+4x3

The roots of polynomial p(x) are: x1​x2​x3​​=0=2​i=−2​i​

Find roots of polynomial $p (x) = 2 x^{5} + 4 x^{3}$

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} x_{3} = 0 = 2 i = - 2 i$