Find roots of polynomial $$ p(x) = 2x^4-x^3+19x^2-9x+9 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.25+0.6614i\\[1 em]x_2 &= 0.25-0.6614i\\[1 em]x_3 &= 3i\\[1 em]x_4 &= -3i \end{aligned} $$Explanation
Polynomial $ 2x^4-x^3+19x^2-9x+9 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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