Find roots of polynomial $$ p(x) = 2x^3-7x^2-3x-2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 3.9445\\[1 em]x_2 &= -0.2223+0.4518i\\[1 em]x_3 &= -0.2223-0.4518i \end{aligned} $$Explanation
Polynomial $ 2x^3-7x^2-3x-2 $ has no rational roots that can be found using Rational Root Test, so the roots were found using qubic formulas.
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