Find roots of polynomial $$ p(x) = 2x^2+8x+10 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -2+i\\[1 em]x_2 &= -2-i \end{aligned} $$Explanation
The solutions of $ 2x^2+8x+10 = 0 $ are: $ x = -2+i ~ \text{and} ~ x = -2-i$.
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