Find roots of polynomial $$ p(x) = 2x^2+8x-78 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4.5574\\[1 em]x_2 &= -8.5574 \end{aligned} $$Explanation
The solutions of $ 2x^2+8x-78 = 0 $ are: $ x = -2-\sqrt{ 43 } ~ \text{and} ~ x = -2+\sqrt{ 43 }$.
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