The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.634\\[1 em]x_2 &= -2.366 \end{aligned} $$The solutions of $ 2x^2+6x+3 = 0 $ are: $ x = -\dfrac{ 3 }{ 2 }-\dfrac{\sqrt{ 3 }}{ 2 } ~ \text{and} ~ x = -\dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 3 }}{ 2 }$.
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