Find roots of polynomial $$ p(x) = 2x^2+4x-8 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.2361\\[1 em]x_2 &= -3.2361 \end{aligned} $$Explanation
The solutions of $ 2x^2+4x-8 = 0 $ are: $ x = -1-\sqrt{ 5 } ~ \text{and} ~ x = -1+\sqrt{ 5 }$.
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