Find roots of polynomial $p (x) = 2 x^{2} + 3 x - 14$

Answer

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} = 2 = - \frac{7}{2}$

Explanation

The solutions of $2 x^{2} + 3 x - 14 = 0$ are: $x = - \frac{7}{2} and x = 2$ .

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.

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Find roots of polynomial p(x)=2x2+3x−14

The roots of polynomial p(x) are: x1​x2​​=2=−27​​

Find roots of polynomial $p (x) = 2 x^{2} + 3 x - 14$

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} = 2 = - \frac{7}{2}$