Find roots of polynomial $p (x) = 2 x^{2} + 3 x$

Answer

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} = 0 = - \frac{3}{2}$

Explanation

Step 1:

Factor out $x$ from $2 x^{2} + 3 x$ and solve two separate equations:

2 x^{2} + 3 x x \cdot (2 x + 3) x = 0 or 2 x + 3 = 0 = 0 = 0

One solution is $x = 0$ . Use second equation to find the remaining roots.

Step 2:

To find the second zero, solve equation $2 x + 3 = 0$

2 x + 3 2 \cdot x x = 0 = - 3 = - \frac{3}{2}

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Find roots of polynomial p(x)=2x2+3x

The roots of polynomial p(x) are: x1​x2​​=0=−23​​

Find roots of polynomial $p (x) = 2 x^{2} + 3 x$

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} = 0 = - \frac{3}{2}$