Find roots of polynomial $$ p(x) = 2x^2+28x-858 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 14.8632\\[1 em]x_2 &= -28.8632 \end{aligned} $$Explanation
The solutions of $ 2x^2+28x-858 = 0 $ are: $ x = -7-\sqrt{ 478 } ~ \text{and} ~ x = -7+\sqrt{ 478 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator