Find roots of polynomial $$ p(x) = 2x^2+26 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \sqrt{ 13 }i\\[1 em]x_2 &= -\sqrt{ 13 }i \end{aligned} $$Explanation
The solutions of $ 2x^2+26 = 0 $ are: $ x = \sqrt{ 13 } i ~ \text{and} ~ x = -\sqrt{ 13 } i $.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator