Find roots of polynomial $$ p(x) = 2x^2+102x-2376 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 17.3748\\[1 em]x_2 &= -68.3748 \end{aligned} $$Explanation
The solutions of $ 2x^2+102x-2376 = 0 $ are: $ x = -\dfrac{ 51 }{ 2 }-\dfrac{ 3 \sqrt{ 817}}{ 2 } ~ \text{and} ~ x = -\dfrac{ 51 }{ 2 }+\dfrac{ 3 \sqrt{ 817}}{ 2 }$.
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