Find roots of polynomial $$ p(x) = 2x^2-4x+8 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1+\sqrt{ 3 }i\\[1 em]x_2 &= 1-\sqrt{ 3 }i \end{aligned} $$Explanation
The solutions of $ 2x^2-4x+8 = 0 $ are: $ x = 1+\sqrt{ 3 }i ~ \text{and} ~ x = 1-\sqrt{ 3 }i$.
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