The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0\\[1 em]x_2 &= 2 \end{aligned} $$Step 1:
Factor out $ \color{blue}{ 2x }$ from $ 2x^2-4x $ and solve two separate equations:
$$ \begin{aligned} 2x^2-4x & = 0\\[1 em] \color{blue}{ 2x }\cdot ( x-2 ) & = 0 \\[1 em] \color{blue}{ 2x = 0} ~~ \text{or} ~~ x-2 & = 0 \end{aligned} $$One solution is $ \color{blue}{ x = 0 } $. Use second equation to find the remaining roots.
Step 2:
To find the second zero, solve equation $ x-2 = 0 $
$$ \begin{aligned} x-2 & = 0 \\[1 em] x & = 2 \end{aligned} $$